[Simple Program for velocity of light eliminates Expansion and Big Bang] - A New Kind of Science: The NKS Forum

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Simple Program for velocity of light eliminates Expansion and Big Bang

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Posted by: MikeHelland

Here's a complete description of the graphs:

|123456|

if X = 3, then it's charted like this:

|..X...|


Ok.


So step 1 X is at 1.

|X.....| (step 1)

On step 2 X is at 3. It's velocity is 2.

|..X...| (step 2)

On Step 3 it is at 4, so its velocity was 1.

|...X..| (step 3)

It's slowing down, when shown together, it looks like this:

|X.....| (step 1)
|..X...| (step 2)
|...X..| (step 3)

If you drew a line through the Xs it would be a curve that depicts
deceleration.

Now the same three steps, shown while zooming-in :

|X.....|
| . . X. . . |
|  .  .  . X.  .  |

A line through these Xs would be a straight line, that depicts a
constant velocity.

If we interpret the zoom as the literal expansion of space, then:

v = d / t

d increases proportionately with the t, and the velocity stays the same.

If you don't interpret the zoom as expansion, then d stays the same, and a decelerating v and inversely increasing t match the same data.



Posted by: MikeHelland

Here's an example of a rule that could be an alternate interpretation of Hubble's Law, instead of light moving at a constant speed in expanding space, instead light decelerates in static space after a few hundred million light years.

code:
photon_count = 0 do while photon_count < 10 photon_count = photon_count + 1 dimension photon_array[photon_count] photon_array[photon_count] = createobject("photon", photon_count) * go a while before creating another photon for iii = 1 to 4.2 * 10^5 for jjj = 1 to photon_count photon = photon_array[jjj] photon.move() endfor endfor ?.t. enddo create cursor photons (n i, x n(20,5), c n(10,6)) for jjj = 1 to photon_count photon = photon_array[jjj] insert into photons (n, x, c) values (photon.n, photon.x, photon.c) endfor browse copy to decelerated type csv define class photon as custom x = 0 && position in light years c = 1 && speed in light years per year i = 0 && iterations n = 0 && identification function move this.i = this.i + 1 this.x = this.x + this.c * We've been traveling for 1 million light years, slow down if this.i = 10^6 this.i = 0 this.c = this.c - 0.00002 ?this.c, this.x, this.n endif return function init(tnPhotonCount) this.n = tnPhotonCount return enddefine


That sends 10 photon's going around, and since they are emitted at
different times, they are traveling at different decelerated
velocities.

Here is the result in CSV format:

n,x,c
1,4199864.00020,0.999920
2,3779893.20022,0.999940
3,3359918.40022,0.999940
4,2939942.40020,0.999960
5,2519959.20014,0.999960
6,2099976.00007,0.999960
7,1679986.40005,0.999980
8,1259994.80002,0.999980
9,840000.00000,1.000000
10,420000.00000,1.000000





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